Trying to figure out how to code something but not quite sure where to start. Part of a strategy needs to find the time or bar number of lowest low or highest high of the oscillator between the current cross and the last cross of the zero line. In other words, if the oscillator is crossing 0 on this bar, go back and find the last cross of 0. Between this bar and the bar that the oscillator last crossed zero, find the bar with the highest high or lowest low. Conceptually it seems easy but I don't have a clue where to start. Would this have to be done in a loop structure working backward to check each bar for a cross or can I use something with the Cross command and a qualifier for the last occurance like [1]?

If anyone can give me an idea of where to start I'd appreciate it. Thanks!

tozwp 

Trying to figure out how to code something but not quite sure where to start. Part of a strategy needs to find the time or bar number of lowest low or highest high of the oscillator between the current cross and the last cross of the zero line. In other words, if the oscillator is crossing 0 on this bar, go back and find the last cross of 0. Between this bar and the bar that the oscillator last crossed zero, find the bar with the highest high or lowest low. Conceptually it seems easy but I don't have a clue where to start. Would this have to be done in a loop structure working backward to check each bar for a cross or can I use something with the Cross command and a qualifier for the last occurance like [1]? If anyone can give me an idea of where to start I'd appreciate it. Thanks!

don't look back, look forward.


initialize 2 variables: a bar counter, and a maxvalue.

start with the first cross,

as soon as the osc cross above zero,
barcounter = currentbar ( timecount if you wish)
maxvalue = osc

next bar:
if osc > maxvalue then do the above assignment again.

keep doing this on every bar and you will always know the max value of the osc and the bar number of that occurence.


when the osc cross zero again, the variables will be re-initialized.

Thanks! I hadn't thought of working forward with this. I figured it would be simpler to wait for the event and then work backwards. I think I can manage to put together something using your technique. Appreciate the help!

tozwp 

Thanks! I hadn't thought of working forward with this. I figured it would be simpler to wait for the event and then work backwards. I think I can manage to put together something using your technique. Appreciate the help!

You are welcome.

Please press the "Thanks" button if you like the answer.