Hey C# Guys,

i have a question about an entry for the strategy that uses 2 algorithms to generate signals.Suppose both algorimths coded to generate a signals on Bar[0].But that`s not always correspond.There are instancies,where the first algo triggers on Bar[1] and the second on Bar[0].So the question is,is there a workaround to add some degree of freedom to the second Algorithm.So if,suppose the X algorithm triggered on Bar[0],how do i get the Y algorithm triggered together with the X,but on any Bars within a certain limit.Example,the X algo triggerd at Bar[0] + the Y algo triggered at any Bars[2]or[1]or[0]or[-1]or[-2] == true

How do i achiev that?

Thanks in advance!

Cachevary 

Hey C# Guys, i have a question about an entry for the strategy that uses 2 algorithms to generate signals.Suppose both algorimths coded to generate a signals on Bar[0].But that`s not always correspond.There are instancies,where the first algo triggers on Bar[1] and the second on Bar[0].So the question is,is there a workaround to add some degree of freedom to the second Algorithm.So if,suppose the X algorithm triggered on Bar[0],how do i get the Y algorithm triggered together with the X,but on any Bars within a certain limit.Example,the X algo triggerd at Bar[0] + the Y algo triggered at any Bars[2]or[1]or[0]or[-1]or[-2] == true How do i achiev that? Thanks in advance!

Hi @Cachevary,

I will make some guesses as some of the missing information. I assume you are trying to do this within a single strategy. There is no way to "look ahead" so your [-1] is invalid. I would love it in the next NT to have them give use the future, so what I think you are looking for is to trigger with an AND type of relationship.

When you see the conditions true set a global variable like:
m_ConditionX=true
m_ConditionY=true

then:
if (m_ConditionX && m_ConditionY)
{
enter/exit
}

Be sure to reset the X&Y conditions when you don't think they are valid (true).

Another means would be to simply keep checking for Y when you see X is try. This would be useful if Y is complex and difficult to track. Depending upon what "Trigger" is, there are functions that look back such as MAX(barsback)[0] which you can use to check for Y condition. Difficult to answer in this generic form of a question.

Hello guys,

need assistance in building conditions.

I have:

 

Code

(this.super.Values[0][1] == this.super.Values[3][1] || this.super.Values[1][1] == this.super.Values[3][1] || this.super.Values[2][1] == this.super.Values[3][1])

I need this.super.Values[3][1] to be equal to any other of the 3 sets when on Bar[1].

Suppose there were the following sets that matched:

this.super.Values[0][1] == this.super.Values[3][1]

Now,on bar[0] i need the this.super.Values[3][0] be grater or less then the this.super.Values[0][0] set,i.e this.super.Values[0][0] <or> this.super.Values[3][0].

How do i accomplish that?Please advise!

Thank you.