Hi -

I am aware of how to get the highest high/lowest low within the last X number of bars AND how to determine how many bars back each of those is.

What I'd like to do is find the highest high within X number of bars PRIOR to the highest high within X number of bars.

Huh, you say?

So, let's say I use MAX(High, 20)[1].
That tells me what the highest high in the last 20 bars was.
Then I use HighestBar(High, 20) and that tells me the actual value of that highest high.

Now, I want to find the highest high within the 20 bars prior to the high I just found, above.

Can anyone suggest code to do this? Or point to someone else's solution?

Thanks, in advance.

(My intention is to home in on the high/low cycles within a trading range, figuring out the width of the range and how many bars apart the highs and lows are.)

DavidBodhi,

one approach would be to loop over the desired bars once you have the bar number of the highest high.
You could adjust the code in the first post here, to loop over the 20 bars to the left of the bar that returned the highest high:

Efficient Code for finding highest high and lowest lows of a range of bars. Hi I'm quite new to C# and ninja script and am convinced there must be a better way to do this... I'm trying to find the lowest low and highest high for a range of bars - (let's say 9 for the sake of argument) - e.g. so I can code a Tenkan …

As you are using Max in your code already, you should also be able to get the value using:

 

Code

int barsAgo = HighestBar(High, 20); double HighestH2 = MAX(High, 20)[barsAgo+1];

Regards,

ABCTG

ABCTG 

DavidBodhi, one approach would be to loop over the desired bars once you have the bar number of the highest high. You could adjust the code in the first post here, to loop over the 20 bars to the left of the bar that returned the highest high: Efficient Code for finding highest high and lowest lows of a range of bars. Hi I'm quite new to C# and ninja script and am convinced there must be a better way to do this... I'm trying to find the lowest low and highest high for a range of bars - (let's say 9 for the sake of argument) - e.g. so I can code a Tenkan … As you are using Max in your code already, you should also be able to get the value using:   Code int barsAgo = HighestBar(High, 20); double HighestH2 = MAX(High, 20)[barsAgo+1]; Regards, ABCTG

Thanks, ABCTG. That will work well for the value of the previous high.

I'll also need the number of bars back that previous high occurred. I'm not much of a programmer, or I'm sure I'd see immediately how to look at all the prior closes from [1] to [barsAgo+1], but that code isn't clear to me. I'll do some research on that, unless you can offer another concise method.

Thanks, again.

DavidBodhi,

you are welcome. This would be something you can accomplish with the loop from the link, too. While you loop over the bars, save the high into your variable in case it's higher than the currently found highest high and save the number of bars this high is back in another variable.

Regards,

ABCTG

ABCTG 

DavidBodhi, you are welcome. This would be something you can accomplish with the loop from the link, too. While you loop over the bars, save the high into your variable in case it's higher than the currently found highest high and save the number of bars this high is back in another variable. Regards, ABCTG

Thanks, again.

I'll look into that.