Hello everyone,

I need your help with a code that finds the HIGH and LOW between the last 3 bars ( red boxes ) and the next 3 bars without taking into account the previous 3 as shown in the figure. To perform the following calculation.

S = (4*X + 3*X[1] + 2*X[2] + X[3])

I have tried but I have not found a solution. Thank you for your time.

Not sure if this is what you are looking for... (not checked)

var:X(0),X1(0),X2(0),X3(0),X4(0);

X=(maxlist(high,high[1])+minlist(low,low[1]))/2.

X1=(maxlist(high[2],high[3],high[4])+minlist(low[2],low[3],low[4]))/2.

X2=(maxlist(high[5],high[6],high[7])+minlist(low[5],low[6],low[7]))/2.

X3=(maxlist(high[8],high[9],high[10])+minlist(low[8],low[9],low[10]))/2.

X4=(maxlist(high[11],high[12],high[13])+minlist(low[11],low[12],low[13]))/2.

Kevin thanks for your time, maybe my explanation was no the better,


Attached new imagen explaining better,
the first imagen (red boxes) was hand draw.

The idea is to find the Highest and Lowest in the 3x bars interval formed, like you can see in the pic.
calculate and storage ‘X’ to get data .....X, X[1], X[2]........ so on.
You can see part of code.

Where: X ‘Variable to store, ” it can be another letter , X= (H+L)/2
H= Highest of 3 bars interval
L= Lowest of 3 bars interval

// -----------------------------------------------
Vars: X(0), S(0), D(0);

X= (H+L)/0.5;

If CurrentBar > 5 Then Begin

S = (4*X + 3*X[1] + 2*X[2] + X[3]) / 10; // Calculate S with X[1],.......X[3]
D = (.0962*S + .5769*S[2] - .5769*S[4]- .0962*S[6]); // Calculate D with S[1],.......S[6]

{……….. part of the code.
.........
}

End;

//-----------------------------------------


Regards,
Carlos


I

kevinkdog 

Not sure if this is what you are looking for... (not checked) var:X(0),X1(0),X2(0),X3(0),X4(0); X=(maxlist(high,high[1])+minlist(low,low[1]))/2. X1=(maxlist(high[2],high[3],high[4])+minlist(low[2],low[3],low[4]))/2. X2=(maxlist(high[5],high[6],high[7])+minlist(low[5],low[6],low[7]))/2. X3=(maxlist(high[8],high[9],high[10])+minlist(low[8],low[9],low[10]))/2. X4=(maxlist(high[11],high[12],high[13])+minlist(low[11],low[12],low[13]))/2.

Sorry, I am unclear what you want. Maybe someone else will understand.

Hi Kevin,

For example, if I have a 5 minutes chart, 3 bars in the that interval are 1 bar in a 15 min chart. Then H and L in 15 min chart, is the same the H and L en 5 min chat ( 3 bars x 5 min).

I want to find the H and L for 15 min bar, but in the 5 min chart. for that the 3 bars interval.

I hope you can help me, please.
thank you,

kevinkdog 

Sorry, I am unclear what you want. Maybe someone else will understand.

Carlera 

Kevin thanks for your time, maybe my explanation was no the better, Attached new imagen explaining better, the first imagen (red boxes) was hand draw. The idea is to find the Highest and Lowest in the 3x bars interval formed, like you can see in the pic. calculate and storage ‘X’ to get data .....X, X[1], X[2]........ so on. You can see part of code. Where: X ‘Variable to store, ” it can be another letter , X= (H+L)/2 H= Highest of 3 bars interval L= Lowest of 3 bars interval // ----------------------------------------------- Vars: X(0), S(0), D(0); X= (H+L)/0.5; If CurrentBar > 5 Then Begin S = (4*X + 3*X[1] + 2*X[2] + X[3]) / 10; // Calculate S with X[1],.......X[3] D = (.0962*S + .5769*S[2] - .5769*S[4]- .0962*S[6]); // Calculate D with S[1],.......S[6] {……….. part of the code. ......... } End; //----------------------------------------- Regards, Carlos I

x=(highest(h[1],3)+lowest(L[1],3))/2
S = (4*X + 3*X[3] + 2*X[6] + X[9]) / 10

or

inputs: n(3," bars interval"),n1(1200,"total bars");
var: i(0),j(0);
array: x[400](0),s[400](0);

If CurrentBar > 5 Then Begin
for i=0 to floor(n1/n) // keep integer
x[i]=(highest(h[n*I+1],n)+lowest(L[n*i+1],n))/2;

for i=0 to floor(n1/n)
begin

for j= n+1 downTo 1
s[i]=s[i]+j*x[n+1-j];

s[i]=s[i]/((n+2)*(n+1)/2); //wma
end ;

end;
D = (.0962*S[0] + .5769*S[2] - .5769*S[4]- .0962*S[6]); // Calculate D with S[1],.......S[6]

{……….. part of the code.
.........
}

End;